how to prove that the sp3, sp2 and sp orbitals of CH​3-CH=CH-CH2-C=_C-CH3? {C=_C is triple bond}

Dear Student,

For the given molecule,
CH3-CH=CH-CH2-CC-CH3 1           2          3          4           5       6     7

There are three carbon atoms(1,4,7) which have a single bond to other carbon atoms. They are bonded to four entities. Thus, they are sp3 hybridized. There are four hybridized orbitals in sp3( s + 3p)
Total sp3 orbitals = 3 atoms x 4 orbitals = 12

There are two carbon atoms (2,3) which have one double bond between them and two single bonds to other atoms(C,H).
They follow sp2 hybridization. There are three sp2 orbitals.
Total sp2 orbitals = 2 atoms x 3 orbitals = 6 orbitals

There are two carbon atoms(5,6) which have one triple bond between them and one single bond with other atoms(H).
They follow sp hybridizaton. There are two sp orbitals.
Total sp orbitals = 2 atoms x 2 orbitals = 4 orbitals

Ratio of number of orbitals is:
sp3 : sp2 : sp = 12 : 6 : 4 = 6 : 3 : 2

Hope it helps.

Regards

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question contd,
.... are in the ratio 6:3:2?

It is an edit to the incomplete question .

Plz do consider the question with the edit.
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