How to shade region for x: (ii) Minimize x = 4x+5y subject to 2 x + y ≥ 7 , 2 x + 3 y ≤ 15 , x ≤ 3 , x ≥ 0 , y ≥ 0 . solve using graphical method. Share with your friends Share 1 Lovina Kansal answered this Dear student We have,Minimise z=4x+5ysubject to 2x+y≥7, 2x+3y≤15, x≤3,x≥0,y≥0Convert the given inequations into equations,we obtain the following equations:2x+y=72x+3y=15x=3x=0 and y=0The lines 2x+y=7 meets the coordinate axis at 3.5,0 and 7,0.Join these points to obtain the line 2x+y=7.Clearly, (0,0) does not satisfies the inequation 2x+y≥7.So, the region in xy-plane that does not contains the origin represents the solution set of the given equation.The line 2x+3y=15 meets the coordinate axis at 7.5,0 and (0,5).Join these points to obtain the line 2x+3y=15.Clearly, (0,0) satisfies the inequation 2x+3y≤15.So, the region in xy-plane that contains the origin represents the solution set of the given equation.The line x=3 meets the coordinate axis at 3,0 Join these points to obtain the line x=3.Clearly, (0,0) satisfies the inequation x≤3.So, the region in xy-plane that contains the origin represents the solution set of the given equation.Region represented by x≥0 and y≥0Since every point in the first quadrant satisfies these inequations.So, the first quadrant is the region represented by the inequations.These lines are drawn using a suitable scale. Regards 0 View Full Answer Anmol answered this Sorry, I'm not a maths student I would have answered if I had been one... -1