How to solve number 7?
It is based on Gay- Lussac's Law. The reaction involved is:
N2 + 3H2 à 2NH3
From the above reaction:
4 moles of reactants (1 of N2 and 3 of H2 ) react to form 2 moles of product.
If only 10% of conversion takes place then reactant reacted will be 0.4 moles.
If only 0.4 moles reactant reacted, then the product formed will be 0.2 moles of ammonia.
Let us assume molar volumes of each reactant are used. (1 mole = 22.4 litres)
Therefore 8.96 litres (0.4 moles) of reactants (H2 and N2) are reacted to form 4.48 litres (0.2 moles) of product (ammonia) is formed.
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