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how to solve tan^-1 2x/1-x² + cot^-1 1-x²/2x = pie/3

\tan^{- 1} (\frac{2 x}{1 - x^{2}}) + c o t^{- 1} (\frac{1 - x^{2}}{2 x}) = \frac{π}{3} A s \tan^{- 1} x = c o t^{- 1} \frac{1}{x} S o \tan^{- 1} (\frac{2 x}{1 - x^{2}}) + \tan^{- 1} (\frac{2 x}{1 - x^{2}}) = \frac{π}{3} S o 2 \tan^{- 1} (\frac{2 x}{1 - x^{2}}) = \frac{π}{3} O r \tan^{- 1} (\frac{2 x}{1 - x^{2}}) = \frac{π}{6} S o \tan (\tan^{- 1} (\frac{2 x}{1 - x^{2}})) = \tan \frac{π}{6} O r \frac{2 x}{1 - x^{2}} = \frac{1}{\sqrt{3}} O r x^{2} + 2 \sqrt{3} - 1 = 0 O r x = - \sqrt{3} \pm 2 (a n s)

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