# How to solve the question

Sum of all angles of a triangle is 180 degrees. Thus angle C = 180-(90+30)=60 degrees.

Side opposite to angle A=BC.

i.e Side opposite 30 degrees = BC=1/2* Hypotenuse

i.e Hypotenuse=AC = 2*BC=16cm.

Also by Pythagoras Theorem,

AC^2=AB^2+BC^2

Thus, AB^2= AC^2-BC^2

i.e AB^2=256-64=192

i.e AB=8$\sqrt{3}$cm.

Thus the above are the required sides and angles.

Regards.

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