How to solve the question

Dear Student,
Sum of all angles of a triangle is 180 degrees. Thus angle C = 180-(90+30)=60 degrees.
Side opposite to angle A=BC. 
i.e Side opposite 30 degrees = BC=1/2* Hypotenuse
i.e Hypotenuse=AC = 2*BC=16cm.
Also by Pythagoras Theorem,
AC^2=AB^2+BC^2
Thus, AB^2= AC^2-BC^2
​​​​​​i.e AB^2=256-64=192
i.e AB=8$\sqrt{3}$cm.
Thus the above are the required sides and angles.
Regards.