How to solve this
Q.72. Calculate the current (in mA) required to deposit 0.195 g of platinum metal in 5.0 hours from a solution of P t C l 6 2 - : (atomic weight : Pt = 195)
(1) 310
(2) 31
(3) 21.44
(4) 5.36

21.44
  • -5
195g ----- 4×96500 0.195-----(4×96500)÷1000 = 4×96.5 Now we know , Q=it i = (4×96.5)÷(5×60×60) = 21.44
  • -9
Wrong answer...
  • -5
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