How to solve this question?

Dear student,


Average Velocity=Total displacementTotal timeVavg=AB2=2R2=2R2×2=R2,Option 2
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  • 1

Dear student,

3th4 of cricular track is A to B

A= initial position

B= final position

 

length of the straight line joining initial and final position.

  1. displacement= AB= (take squareroot) OA square + OB square
  2. AB = (take squareroot) R square+R square= R square2
  3. so, displacement R square 2
Regards
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