How to solve this

How to solve this Z o o O 8

Dear student

Let us assume that the reaction is First order.
Thus the reaction will have to obey the rate law for first order.



$$\begin{gathered} K=\frac{2.303}{t}\log \frac{a}{a-x} \\ K=\frac{2.303}{t}\log \frac{V_{\infty }}{V_{\infty }-V_t} \\ Here V_{\infty } =1.62 \\ The value of k is found out for each : \\ time V_t V_{\infty }-V_t K=\frac{2.303}{t}\log \frac{V_{\infty }}{V_{\infty }-V_t} \\ 0 0 1.62-0=1.62 K=\frac{2.303}{0}\log \frac{1.62}{1.62} = 0 \\ Similarly for the second time interval K is calculated. \\ if the K values come almost equal , it is proved that the reaction is first order. \\ But here as V_{\infty } =1.62 so V_{\infty }-V_t comes out to be negative, which is not possible \\ as 1.62-10= -8.38 \\ So kindly verify the question. \end{gathered}$$
Regards