how to use log & antilogtable to find square roots

Always use the following steps:

see lets find out square root of 33.

x=root 33

putting log on both sides

log x = log (33)^{12}

now, look for 0 house of 33 i.e column of 0 in 33

its 5185 now 33 has two digits so 2-1 = 1

so, log (33)^{1/2} =1/2 * 1.5185

= 0.7592

now log x = 0.7592

x = antilog (0.7592)

look in 9 th column of .75 in antilog table, itz 5741

now see 2nd column in mean difference , itz 3

now add both of them i.e 5741+3 = 5744

so antilog (0.7592) = 5744

before decimal we have 0 so add 1 n the answer u got put decimal after 1 digit

i.e 5.744

so the root of 33 is 5.744.

if it helps one thumbs up plzz.....

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