http:// www.meritnation.com /ask-answer/question/ in-the- area-of-a-circle-if- its-radius-is-increased-by-4/ areas-related-to-circles/ 3777090
1. New radius = r + 40/100 x r
= r(140-100)
why is 100 added to the numerator??
2. Increase in surface area = [pi (1.4r sq.) - pir sq.]/ pir sq.
why is original area not only subtracted but also divided by new area

Here is the complete solution.

Let the original radius of the circle = rOriginal area of circle, A = πr2Now, rate of increase = 40%Increase in radius = 40% of r = 40100r = 2r5Now, new radius, r1 = original radius + increase in radiusr1 = r + 2r5 = 7r5New area,A1 = πr12 = π7r52 = 4925πr2Now, increase in area = A1 - A = 4925πr2 - πr2 = 2425 πr2      Increase % = increase in areaoriginal area×100%increase % = 2425πr2πr2×100%increase %  = 2425×100% = 96%

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