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Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water. What mass of oxygen gas

would be required to react completely with 3g of hydrogen gas?

Hydrogen and oxygen combine in the ratio of 1:8 means that 1g of hydrogen gas requires 8g of oxygen gas to form water.

Therefore, 3g of Hydrogen gas will require = 8 * 3

= 24 g of oxygen

Thus, 24g of the oxygen gas would be required to react completely with 3g of hydrogen gas to form water.

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By the law of constant properties, whatever be the mass of hydrogen or oxygen, they should be in a ratio of 1:8.

Now,

We have 3g of hydrogen gas.

We have to find O2's mass to get both of them in the ratio of 1:8.This means-------------

3:x=1:8

3/x=1/8

1/x=1/8*1/3

1/x=1/24

x=24

This means that x i.e mass of O2 is equal to 24g

Thumbs up plz!!!!!!!!!!!

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H2O ratio 1:8 by mass

H2O 2g of hydrogen gas combine with 16g of oxygrn gas

1g of H2 - = 18/2 g of O2 gas = 8g of O2gas

3g of H2 gas - 16/2*3 = 24g of oxygen gas

HOPE THIS HELPS ..... PLS THUMBS UP :)

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