i a circuit with a coil of resistance 2 ohms, the magnetic flux changes from 2 wb to 10 wb in 0.2 second. the charge that flows in the coil during this time is

5 coulomb

4 coulomb

1 coulomb

0.8 coulomb

please help me xperts

First calculate EMF=-rate of chang of flux=-(2-10)/.2=40 V

Now I=V/R=40/2=20A i.e 20 Columb/sec as I=q/t.

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 hey arshad i want full answer, if u dont have have the full answer so  dare u to answer my question, ok

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