I cant undestand this formula while answering the question below a ³+b ³+c ³= 3abc If a+b+c=0 , thenprovethat a²/bc+b²/ca+c²/ab=3

Please don't give me the link to the quetion answered by Harleen Birdi (MeritNation Expert).

JUST EXPLAIN HOW YOU GOT THIS FORMULA a ³+b ³+c ³= 3abc.

Dont give the link:

Just explain how u got the formulaa³+b³+c³= 3abc

You have given me the link 2 times.

Frnd Abdullah it's correct that if a+b+c=0 than a3+b3+c3-3abc = (a+b+c) (a2+b2+c2-ab-bc-ac), hence it's identity i cant expand it or explain it in other way as it's identity, you have to practise it.

Ok,have a good day my frnd

a3+b3+c3-3abc = (a+b+c) (a2+b2+c2-ab-bc-ca)

if a+b+c=0 than rhs side will be

0 X (a2+b2+c2-ab-bc-ca)

=0

now consider lhs side

a3+b3+c3-3abc = 0

hence a3+b3+c3 = 3abc

i hope it is clear