I did not get the force on RS ...?what is the nt force ?how do v get it ?by subtracting ?

I did not get the force on RS ...?what is the nt force ?how do v get it ?by subtracting ? p o,V/a2 200-v'fö) 20 100 It is obvious that all the values are in good agreement with the theoreti Write the expression for the magnetic moment (m) due to a planar square loop "f side •r carrying a steady current in a vector form. In the given figur this loop is placed in a horizontal plane near a long straight conductor carrying a steady current II at a distance I as shown. Give reasons to explain that the loop will experience net force bu t no torq ue. W rite the expression ror this force acting op the loop. [CBSE Delhi 20101 Magnetic moment due to a planar square loop of side I carrying current I is m IA For square loop A 12 m = 1 12 h where h is unit vector-normal to loop. Magnetic field due to current carrying wire at the lcxation of loop is directed downward perpendicular to plane of loop. Force on QR and SP are equal and opposite. so net force on these sides is zero. = 11 Force on side P Q. F PQ From on side RS FRS = 110/ NetforceF-Fpe = p S = zero That is loop experiences a repulsive force but no torque. 3. A parallel plate capacitor iS being charged by a time varying current. Explain brieny how ampere' circuital law is generalized to incorporate the effect due to the displacement current. 2011 Consider a parallel plate capacitor, being charged by a battery. A time varying current flowing throug the capacitor. If we consider only the conduction current I, then we apply Circuital Law to closed loops Cl and C2, then we get