I know that Pent-2-ene reacting with HBr yields two product

as 2-Bromopentane and 3-Bromopentane..

But which one is major product?

When pent-2-ene reacts with HBr ,equal amount of 2-bromo pentane and 3-bromopentane are formed because degree of  alkyl substituition is same for both carbons in it.
Where as in another case of  1-pentene ,due to different degree of alkyl substituition 2-bromo-pentene is major product.

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