I need answers for all questions.... No need explanation..
Dear Student,
11) smaller
or
equal in number
12) becquerel
13) decreased
14) eddy current
15)
11) smaller
or
equal in number
12) becquerel
13) decreased
14) eddy current
15)
IN this case, the weight of the drop = electric force exerted by the field
so,
mg = qE
or
q = mg/E
which is the charge on the drop.
thus,
F = mg = 3.2 X 10-13 N
E = 5 X 105 N/C
so,
q = F/E = 3.2 X 10-13 / 5 X 105
or
q = (3.2/5) X 10-18
or the charge on the drop will be
q = 6.4 X 10 -19 C
Regards