I SENT THIS QUESTION MANY TIMES BUT STILL TODAY I HAVEN'T GOT ANSWER FOR THE QUESTION CAN YOU PLEASE SEND - Maths - Simultaneous Linear Equations

Question

I SENT THIS QUESTION MANY TIMES BUT STILL TODAY I HAVEN'T GOT
ANSWER FOR THE QUESTION CAN YOU PLEASE SEND THE ANSWER NOW AS MY
1ST SEMESTER EXAM IS STARTING SOON "AND PLEASE DO NOT SEND ANY
LINKS" Please solve 40th question

40     Solve   :   15 u   +   2 v
  =   17   and   1 u   +   1 v  
=   36 5

Abhishek Kr. Jha · Accepted Answer

Dear student,
Here is the solution of your asked query:
Assuming 1u=x and 1v=y; we have15u+2v=17⇒15x+2y=17 
(i)1u+1v=365⇒x+y=365   
(ii)Multiplying ii by 15 and subtracting (ii) from (i) we get;15x+2y-15x+y=17-15×365⇒15x+2y-15x-15y=17-108⇒13y=91⇒y=9113=7Then, x= 365-7=15      {putting the value of y in (ii)}Therefore, 1u=x=15 ⇒u=5And, 1v=y=7⇒v=17
Regards

I SENT THIS QUESTION MANY TIMES BUT STILL TODAY I HAVEN'T GOT ANSWER FOR THE QUESTION.CAN YOU PLEASE SEND THE ANSWER NOW AS MY 1ST SEMESTER EXAM IS STARTING SOON... "AND PLEASE DO NOT SEND ANY LINKS". Please solve 40th question. 40 . Solve : 15 u + 2 v = 17 and 1 u + 1 v = 36 5