Dear Student, a3a-b+b3b-a⇒a3a-b-b3a-b⇒a3-b3a-b⇒ a–ba2+ab+b2a-b a3–b3=a–ba2+ab+b2⇒a2+ab+b2 Regards

I want the answer

I want the answer Simplify: —

Dear Student,

\frac{a^{3}}{a - b} + \frac{b^{3}}{b - a} \Rightarrow \frac{a^{3}}{a - b} - \frac{b^{3}}{a - b} \Rightarrow \frac{a^{3} - b^{3}}{a - b} \Rightarrow \frac{(a - b) (a^{2} + ab + b^{2})}{a - b} [a^{3} - b^{3} = (a - b) (a^{2} + ab + b^{2})] \Rightarrow (a^{2} + a b + b^{2})

Regards