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(i) Write balanced chemical equations for the following:
    (a) Complete hydrolysis of XeF6.
    (b) Disproportionation reaction of orthophosphorus acid.
(ii) Draw the structure of a noble gas species which is iso-structural with BrO3 –.
(iii) Considering the parameters such as bond dissociation enthalpy, electron gain enthalpy and hydration enthalpy, compare the oxidising power of F2 and Cl2.
(iv) Why is Ka2 << Ka1 for F2SO4 in water?

OR

Explain the following:
(i) Hydrogen fluoride is a weaker acid than hydrogen chloride in aqueous solution.
(ii) PCl5 is ionic in nature in the solid state.
(iii) SF6 is inert towards hydrolysis.
(iv) H3PO3 is diprotic.
(v) Out of noble gases only xenon is known to form established chemical compounds.
 

Dear student
Please find below the solution to the asked query:

Xenon hexafluoride hydrolyzes stepwise-

XeF6 + H2O → XeOF4 + 2 HF

XeOF4 + H2O → XeO2F2 + 2 HF

XeO2F2 + H2O → XeO3 + 2 HF

​ii)XeO3 is isostructural to and has a pyramidal molecular structure.
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The bond dissociation of F2 is greater than Cl2 and Electron gain enthalpy of F2 is less negative than Cl2. This Factors are likely to reduce the oxidising power of F2 as this will not allow F2 to take electrons. But due to very high hydration enthalpy, the energy get compensate and makes F2 a better oxidising agent than Cl2.
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