Identical balls are dropped from sufficient height on a regular interval of t second. Distance between 1st and 2nd ball when the nth ball is dropped is ? Answer is 1/2gt2(2n-3) Share with your friends Share 0 Rajnish Kumar answered this Dear student let the first ball is dropped at t=0 then first ball takes time of (n-1)t and second ball takes time (n-2)tnow s1 =12g{ (n-1)t}2 and s2 =12g{ (n-2)t}2 now seperation between them is s1 -s2=12g{ (n-1)t}2 -12g{ (n-2)t}2=12gt2(2n-3)Regards 2 View Full Answer
