If 0 50 L of a 0 60 M SnSo4 solution is electrolysed for a period of 30 mins - Chemistry - Electrochemistry

Question

If 0 50 L of a 0 60 M SnSo​4 solution
is electrolysed for a period of 30 mins Using a current of 4 60 A
If inert electrode are used, what is the final concentration of
Smn2+ remaining in the solution? ( at wt of Sn=119)

Vartika Jain · Accepted Answer

Dear Student,

Q=I×t    = 4
60×30×60    = 8280 C1 mol of electrons = 96500 CTherefore, Moles of electrons passed in the circuit =828096500=0
0858Sn2+(aq) + 2e- → Sn(s)It takes two moles of electrons to form one mole of SnTherefore, moles of Sn = 0
08582=0
0429Moles of Sn = Moles of Sn2+Concentration of Sn2+=0
04290 50=0 0858 MFinal concentration of Sn2+=0
60-0 0858 =0 514 M

If 0.50 L of a 0.60 M SnSo​4 solution is electrolysed for a period of 30 mins. Using a current of 4.60 A. If inert electrode are used, what is the final concentration of Smn2+ remaining in the solution? ( at.wt. of Sn=119)

If 0.50 L of a 0.60 M SnSo_₄ solution is electrolysed for a period of 30 mins. Using a current of 4.60 A. If inert electrode are used, what is the final concentration of Smn²⁺ remaining in the solution? ( at.wt. of Sn=119)