If 1 is zero of the polynomial p(x) = ax2 - 3(a-1)x - 1, then the value of 'a' is
One of the zeroes of the polynomial is 1 .
i.e. when x = 1 p(x) = 0
Let's put the value of x in the given polynomial
we get , a(1)2 -3(a - 1)1 - 1 = 0
a - 3a +3 -1 = 0
-2a +2 =0
a = -2 / -2
a = 1