If 1 mole of MnO4 oxidizes 2.5 moles of M^x+ then the value of x is (a) 5 (b) 3 (c) 4 (d) 2

Question is not clear but I am providing the solution: Medium of reaction, change in oxidation no. of Mn is not given. Compound should be MnO4- instead of MnO4


Mn7+ + Mx+ Mn2+  + MNo. of equivalents of MnO4- = No. of equivalents of Mmoles ×valency factor=No. of equivalentsso 1×5 = 2.5×valency factor of Mvalency factor of M=2It means the oxidation No. change for Mx+  M is 2 So option D is correct. 
‚Äč

  • 5
NFR
  • 3
What are you looking for?