If 12th March 1986 was Wednesday, then 31st March 1994 would be

Dear Student,

Please find below the solution to the asked query:

Given : On 12th March 1986 was Wednesday . Then 31st March 1994 would be

In a normal year we have 365 days ,

365 days  =  52 weeks and 1 day , So we get 1 odd day

And In leap year we have 366 days ,

366 days  = 52 weeks and 2 day , So we get 2 odd day

Then ,

12th March 1987 will be Wednesday (12th March 1986) + 1 day = Thursday.

12th March 1988 = Thursday + 1 = Friday

12th March 1989 = Friday + 2 = Sunday ( As 1988 is a leap year )

12th March 1990 = Sunday  + 1 = Monday

12th March 1991=Monday + 1 = Tuesday

12th March 1992 = Tuesday + 1 = Wednesday

12th March 1993 = Wednesday  + 2 = Friday ( As 1992 is a leap year )

12th March 1994 = Friday  + 1 = Saturday

So,

31st March 1994 = 12th March + 19 days = Saturday + 2 weeks + 5 days = Saturday + 5 =  Thursday

Therefore,

On 31st March 1994 = Thursday                                       ( Ans )


Hope this information will clear your doubts about PSA Tests .

If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

  • 22
Thursday
  • -10

A leap year has 2 odd days and a normal year has 1 odd day.

12th March 1987 will be Wednesday(12th March 1986)+1 day = Thursday.

12th March 1988=Thursday+2=Saturday(LEAP YEAR)

12th March 1989=Sunday

12th March 1990=Monday

12th March 1991=Tuesday

12th March 1992=Tuesday+2=Thursday

12th March 1993=Friday

12th March 1994=Saturday

31st March 1994=12th March + 19 days = Saturday +19 days=Thursday

So, Thursday is the answer.

  • 6
What are you looking for?