If 18g of glucose is present in 1000g of solvent, the solution is said to be: Share with your friends Share 9 Avni answered this Given mass of glucose = 18 g Mass of solvent = 1000 g Molar mass of glucose = 180 g Molality = Given mass of solute Molar mass of solute×Molar mass of solvent in kgMolatity = 18×1000180×1000 = 0.1 molal 35 View Full Answer