If 18g of glucose is present in 1000g of solvent, the solution is said to be:

Given mass of glucose = 18 g
Mass of solvent = 1000 g
Molar mass of glucose = 180 g
Molality = Given mass of solute Molar mass of solute×Molar mass of solvent in kgMolatity = 18×1000180×1000 = 0.1 molal

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