complementary angles -( sum = 90o)
ATQ,
Let one angle be x
then the other angle = x+8 (angles differ by 8)(given)
THEREFORE,
x + (x+8) = 90o
=> 2x +8 = 90o
=> 2x = (90 - 8)o
=> 2x= 82o
=> x = 82o/2
=> x = 41o
thus, angle one = x = 41o
angle 2 = x+8 = (41 + 8)o
=>angle 2 = 49o
hence, the two complementary angles are - 41 degree and 49 degree.
hope this helps...