If 2 X 10 -3 J of work is done in moving a particle carrying a charge of 10 X 10-6 Coulomb from infinity to a point P. What will be the potential at the point P?

v=w/q
v=2 X 10*-3/10 X 10*-6
V=10*3/5=1000/5= 200
V= 200V
 
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This is the ans from ATHARVA Tope

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