if 2x= 4y=8z and xyz=288,then 1/2x+1/4y+1/8z is equal to (a) 11/8 (b) 11/24 (c)11/48 (d) 11/96 Share with your friends Share 5 Manbar Singh answered this We have, 2x = 4y = 8z⇒2x = 22y = 23z⇒x=2y = 3zNow, xyz = 288⇒2y . y . 23y = 288⇒y3 = 216⇒y = 6Now, x = 12and z = 4now, 12x + 14y + 18z = 124 + 124 + 132 = 4+4+396 = 1196 26 View Full Answer