if 2x+y-4=0 is a bisector of angles between the lines a(x-1) + b(y-2) =0,c (x-1) + d(y-2)= 0 the other angular bisector is?

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Please find below the solution to the asked query:

We haveax-1+by-2=0....icx-1+dy-2=0....iiClearly 1,2 lie on both the lines and hence  1,2 is their point of intersection.Both the bisectors will also pass through  1,2One of the bisector is 2x+y-4=0Other bisector will be perpendicular to this bisector. Hence its equation will bex-2y=λIt passes through 1,21-4=λλ=-3Hence equation isx-2y=-3x-2y+3=0 Answer

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