If 31y5 is a multiple of (a) 3 and (b) 9, find the value of y which satisfies the number, where y be any digit.

  • 1
if no is divisible by 9 then it will be divisible by 3 to.'so we have to put a digit which makes the sum of the digits divisible by 9.
thus if we put 0(then sum=9) or 9(sum=18) then no is divisible by 9 as 9 & 18 are divisible by 9
  • 2
What are you looking for?