If 4x^2+y^2=40 and xy=6, find the value of 2x+y?

Dear student,

We have,(2x+y)on squaring(2x+y)2=4x2+y2+2×2x×y           --[using (a+b)2=a2+b2+2ab]=40+4×6                       --[using 4x2+y2=40 and xy=6] =40+24(2x+y)2=64(2x+y)=64(2x+y)=±8

Regards

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