If 5 is a zero of x^3+kx^2+2x+8

Hargun what's the method

-143/25

Let 5 is the zero of polynomial.
P(x)=x^3+kx^2+2x+8.
= (5)^3+k(5)^2+2(5)+8 =0
= 125+25k+10+8=0
=143+25k=0
= 168 k
=k= -168.


Hope your answer. Plz

5 Is The Zero Of The Polynomial x^3 + kx^2 + 2x + 8
Then Substituting 5 for x
(5)^3 + k(5)^2 + 2*5 + 8 = 0
125 + 25k + 10 + 8 = 0
143 + 25k = 0
25k = -143
k = -143/25