If 5 is a zero of x3+kx2+2x+8. Find k. Share with your friends Share 1 Varun.Rawat answered this Let px = x3 + kx2+2x+8Since, 5 is a zero of px, then p5 = 0⇒53 + k52 + 25 + 8 = 0⇒125 + 25k + 10 + 8 = 0⇒25k + 143 = 0⇒25k = -143⇒k = -14325 3 View Full Answer Pratyush Gupta answered this 5 is a zero p(5)=(5)3+k(5)2+2(5)+8=0 125+25k+10+8=0 143+25k=0 25k=-143 k=-143/25=6.72 2
