If 50% of reaction is completed in 100 seconds and 75% of reaction is completed in 300 sec than what will be rate of reaction.( PlZ solve correctly because half life period of 75% reaction would be 200 sec, not 300 sec)

Dear Student,

The computation is expressed below,

50% 100 sec75 %  200 sec (as stated)for 50% decomposed remains 50% so,ln A = -kt + ln Aoln 0.5 = -k(100) + ln (1)k =0.00693 sec-1for 75% decomposed remains 25% so,ln 0.25 = -k(200)+ln(1)k=0.00693 sec-1Hence both the reaction gives same rate constant hence the given reactionscheme is first order and its reaction israte of reaction = k[A][B] = 0.00639[1][1] = 0.00693 Ms-1

Regards.

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