​If 500 sound waves are produced in one minute then find the time taken by the vibrating particle to move from its mean position to immediate rarefraction?

sorry tarun not studied the chapter yet
  • -6
yes
  • -11
no
 
  • -13
expert answer it please
  • -5
W.K.T;
Frequency = no.of waves
                     time period
=> Frequency =     500       = 8.3Hz
                         60 seconds
NOW;

( Since, wavelength is the distance between two consecutive rarefactions )
[ ( Since, distance between two consecutive rarefactions is 2( distance the between mean position to immediate rarefaction ) ]

=> Wavelength = 2( distance between mean position to immediate rarefaction )
                        =  Speed of sound  = 340 ms-1 = 40.9638554217m
                              frequency             8.3Hz

=> Distance between mean position to immediate rearefaction = Wavelength
                                                                                                         2
=> ​Distance between mean position to immediate rearefaction = ​40.9638554217m
                                                                                                           2
                                                                                              = 20.4819277108m
NOW,

{Time taken by the vibrating particle to move from its ​mean position to immediate rearefaction}= Distance between mean position to immediate rearefaction   
                                                               Speed of sound

                                   = ​20.4819277108m = 0.06024096385seconds 
                                            340ms-1                                                                       

(Since,1 second = 103milliseconds)
( ​0.06024096385seconds = 60.24096385ms )

THEREFORE;
{Time taken by the vibrating particle to move from its mean position to immediate rearefaction }= 60 millisecond

Thumbs up!!!!!
 
  • 11
Thanks guys!!!
Though I myself figured it out!!!
  • 6
W.K.T; Frequency = no.of waves time period => Frequency = 500 = 8.3Hz 60 seconds NOW; ( Since, wavelength is the distance between two consecutive rarefactions ) [ ( Since, distance between two consecutive rarefactions is 2( distance the between mean position to immediate rarefaction ) ] => Wavelength = 2( distance between mean position to immediate rarefaction ) = Speed of sound = 340 ms-1 = 40.9638554217m frequency 8.3Hz => Distance between mean position to immediate rearefaction = Wavelength 2 => ​Distance between mean position to immediate rearefaction = ​40.9638554217m 2 = 20.4819277108m NOW, {Time taken by the vibrating particle to move from its ​mean position to immediate rearefaction}= Distance between mean position to immediate rearefaction Speed of sound = ​20.4819277108m = 0.06024096385seconds 340ms-1 (Since,1 second = 103milliseconds) ( ​0.06024096385seconds = 60.24096385ms ) THEREFORE; {Time taken by the vibrating particle to move from its mean position to immediate rearefaction }= 60 millisecond Thumbs up!!!!!
  • 0
And is 60msec

  • 12
No these cannot good explain
  • 0
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