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If (9/7)³ X (49/81)^2x-6 =(7/9)⁹ , then what is the value of x?

${(\frac{9}{7})}^{3} \times {(\frac{49}{81})}^{2 x - 6} = {(\frac{7}{9})}^{9} \Rightarrow {(\frac{7}{9})}^{- 3} \times ({(\frac{7}{9})}^{2})^{2 x - 6} = (\frac{7}{9})^{9} \Rightarrow (\frac{7}{9})^{4 x - 12 - 3} = (\frac{7}{9})^{9} \Rightarrow 4 x - 15 = 9 \Rightarrow 4 x = 9 + 15 = 24 \Rightarrow x = \frac{24}{4} = 6$

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