If A(1,2), B(-3,2) , and C(3,-2) be the vertices ofa triangle ABC, show that i) tanA=2, ii)tanB=2/3 and iii) tanC=4/7

The figure is,

The slop of line AB m1= 2-2-3-1=0slop of line AC m2=-2-23-1=-2slop of line BC m3=-2-23+3=-23Now angle between line AB and BC, tanB=m1-m31+m1×m3=0+231-0=23and tanC=m2-m31+m2×m3=-2+231+43=47and tanA=m1-m21+m1×m2=0+21-0=2

  • 5
What are you looking for?