If a b and c are angles of a triangle abc then cos(3a+2b+c/2) + cos(a-c/2)= Share with your friends Share 7 Amrutha answered this Cos (3A+2B+C÷2)+cos (A-C÷2)=zero "0". -7 View Full Answer Trinadh Kondra answered this If a b c are the angles of trianngle abc then cos [3A+2B+C/2]+cos [A-C/2]= please show the answer -1 Nishith answered this Put value 60°in all angles -9 Sathwik answered this Sum of angles of triangle = 180 -9 Rajat answered this Pkease show the solution clearly 4 Pratapreddy answered this If a b and c are angles of a triangle abc then cos(3a+2b+c/2) + cos(a-c/2)= 0
