if a,b,c are angles of triangle such that 0 a,b,c 90 satisfying sin2a+sin2b=sinc then possible values of c are - Physics - Basic Mathematics

Question

if a,b,c are angles of triangle such that 0<a,b,c<90
satisfying sin2a+sin2b=sinc then possible
values of c are

Brijendra Pal · Accepted Answer

Dear Student, sin2A+sin2B = sinC = sin180-A+Bsin2A+sin2B =  sinA+BNow the possible compbination can be A = 45, B = 45 and A+B = 90So we have 12+12= 11= 1So C can be 90 degreeNow again when A = 30, B = 60 or vice versa then again condition is fallowed
But again C = 90 degreeSo C has one value 90 degree
Regards

if a,b,c are angles of triangle such that 0<a,b,c<90 satisfying sin2a+sin2b=sinc then possible values of c are

if a,b,c are angles of triangle such that 0<a,b,c<90 satisfying sin²a+sin²b=sinc then possible values of c are