if a,b,c are in A.P., then prove that 2^ax+1,2^bx+1,2^cx+1 are in g.p.

2 ax + bz + 123= meritnation error !
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a,b,c are in A.P a+c = 2b 2^ax+1+cx+1=2^2(bx+1) 2^ax+1.2^cx+1= 2^2(bx+1) Therefore 2^ax+1,2^bx+1,2^cx+1 are in G.P
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