If a,b,c are in AP as well as in GP then show that a=b=c.

Given : a, b, c are in A.P.

⇒ 2b = a + c  .......(1)

⇒ (2b)2 = (a + c)2

⇒ 4b2 = a2 + c2 + 2ac  ....(2)

Also, 

a, b, c are in G.P.

⇒ b2 = ac  ......(3)

Fron (2) and (3) we get

4ac = a2 + c2 + 2ac

⇒  a2 + c2 + 2ac - 4ac = 0

⇒  a2 + c2 - 2ac = 0

⇒ (a - c)2 = 0

⇒ a - c = 0

⇒ a = c  ....(4)

From (1) and (4) we get

2b = a + a = c + c

⇒ 2b = 2a = 2c

⇒ a = b = c

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