If A,B,C are mutually exclusive and exhaustive events associated with a random experiment and P(B) = 0.6 P(A) and P(C) = 0.2 then find P(A).

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If A,B,C are mutually exclusive and exhaustive events associated with a random experiment and P(B) = 0.6 P(A) and P(C) = 0.2 then find P(A).

We have p(B) = 0.6 p(A) , p(C) = 0.2

 We know A,B,C are mutually exclusive and exhaustive events associated with a random experiment

So, A U B U C = S

 p(A U B U C) = p(S)

P(A U B U C) = 1   …………. (as P(S) = 1)

P(A) + P(B) + P(C) = 1   ……….[By addition theorem]

On Putting the values , we get

 P(A) + 0.6P(A) + 0.2 = 1

1.6P(A) = 1-0.2

P(A) = 0.8/1.6

  = ½ = 0.5