if a ,b,c are the lengths of sides BC ,CA,AB of a triangle ABC proof that

BC+CA+AB=0 and deduce that

a/sinA=b/sinB=c/sinC

refer r.d 25.1 ques 20 and pls answer fast pls of all ques that r asked

in vector geometry

AB+BC+CA=(AB+BC)+CA=AC+CA=AC-CA=0

area of the triangle ABC with the sides a,b and c is given by:

Area=

dividing the whole equation by abc:

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