if a box is pushed across the floor with a force of 130 N the frictional force between the box - Science - Gravitation

Question

if a box is pushed across the floor with a force of 130 N the
frictional force between the box and the floor is 30 N, over a time
period of 5 sec 1 find the net force acting on it 2 acceleration
acting upon the box if it starts from rest and attains certain KE
after being pushed 25 m? 3 find mass of the box 3 what will be the
KE and final velocity

Pintu B. · Accepted Answer

Dear Student ,
1 Net force = 130 -30 = 100 N
2 let the acceleration be f
So ,s=ut+12ft2⇒25=0+12×f×25⇒f=2 m/s23
 Mass =M=Forceacceleration=1302=65 Kg4
 Final velocity =v (let)So , v2=u2+2fs=0+2×2×25=100⇒v=10 m/sSo kinetic energy=12mv2=12×65×100=3250 J

Regards