if a circle centred at(4,3) touches a line x+y=1,then its point of contact is? Share with your friends Share 0 Rahul Raj answered this dear student as the circle touches the line x+y=1so this line is tangent to circleequation of normal at point of contact thus becomesx-y=kit passes through (4,3)so, k=4-3=1point of contact is intersectio of x+y=1 and x-y=1adding we get 2x=2x=1and y=0so point of contact is (1,0) regards 3 View Full Answer