If a complex number lies in the third quadrant, then its conjugate lies in which quadrant?

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Please find below the solution to the asked query:
$$\begin{gathered} \mathrm{Since} \mathrm{complex} \mathrm{number} \mathrm{lies} \mathrm{in} \mathrm{third} \mathrm{quadrant}, \\ \mathrm{z} = -\mathrm{x}-\mathrm{iy} \\ \mathrm{so} \mathrm{it} \mathrm{will} \mathrm{be} \left(-\mathrm{x}, -\mathrm{y} \right) \\ \mathrm{and} \mathrm{its} \mathrm{consjugate} \mathrm{is} \\ \mathrm{z} = -\mathrm{x}+\mathrm{iy} \\ \mathrm{so} \mathrm{it} \mathrm{will} \mathrm{be} \left(-\mathrm{x}, \mathrm{y} \right) \mathrm{and} \mathrm{it} \mathrm{will} \mathrm{lie} \mathrm{on} \mathrm{second} \mathrm{quadrant}. \end{gathered}$$




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