# If a dielectric slab between the parallel plates of a capacitor is replaced by a metal plate of same thickness t < d where d is the separation between the plates of the capacitor, how does its capacitance change?

Dear Student,

Please find below the solution to the asked query:

Capacitance of the capacitor initially, when there is no metal plate is,

$C=\frac{{\epsilon}_{0}A}{d}$

Now, if a metal plate of thickness *t* is introduced between the plates of the capacitor. Then the distance between the plates of a capacitor becomes *(d-t)* because, the dielectric constant for conductor is *infinity*. So, the capacitance becomes,

$C\text{'}=\frac{{\epsilon}_{0}A}{d-t}\Rightarrow C\text{'}=\left(\frac{d}{d-t}\right)\left(\frac{{\epsilon}_{0}A}{d}\right)\phantom{\rule{0ex}{0ex}}\Rightarrow C\text{'}=\left(\frac{d}{d-t}\right)C$

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