if a = i+2j+3k, b= 2i-j+k, c=i+j-2k how i can verify that across(b cross c)= (a.b)c i m getingif a =across(b cross c)= -9i+3k and (a.b)c = 3i+3j-6k explain me how both r equal

2- how to cal volm of parallelopiped whose continuous edge r represented by vectors a= 2i-3j+k, b= i-j+2k, c= 2i+j+k explain the concept of this also

(1) The formula should be:-

 a×b×c=a.cb - a.bc

This is called the Vector Triple Product, or Triple Product Expansion, or also Lagrange's Formula.

Its verification for the 3 given vectors is as follows:-

LHS=i^+2j^+3k^×2i^-j^+k^×i^+j^-2k=i^+2j^+3k^×i^+5j^+3k=-9i^+3k

RHS=2i^-j^+ki^+2j^+3k^.i^+j^-2k^ - i^+j^-2k^i^+2j^+3k.2i^-j^+k=2i^-j^+k1+2-6 - i^+j^-2k^2-2+3=-6i^+3j^-3k^-3i^+3j^-6k^=-9i^+3k^

So, LHS=RHS
Hence Proved.

(2)

 

Volume = Area of base x Height
           =a×b.ccosϕ=a×b.c

So, the volume of the given parallelopiped = 2i^-3j^+k^×i^-j^+2k^.2i^+j^+k^=-5i^-3j^+k.2i^+j^+k^
=-10-3+1=12

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