If A is a non-singular matrix and (A-2l )(A-4l )= [0 ] then 1+6A+1+3A inverse is

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Please find below the solution to the asked query:

We haveA-2IA-4I=0HenceEitherA=2IorA=4IWhen A=2IWe haveS=16A+13A-1=26I+132I-1=13I+1312I As I-1=I=13I+16I=I2=120012When A=4IWe haveS=16A+13A-1=46I+134I-1=23I+1314I As I-1=I=23I+112I=912I=34I=340034

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1/6A+1/3(Ainverse) is to be calculated.
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