# if a line is equally inclined to axes ,prove that its slope is +_1

respectively.

If the line is equally inclined with the axes, then $\alpha =\beta \phantom{\rule{0ex}{0ex}}\Rightarrow \alpha +\beta =2\alpha \phantom{\rule{0ex}{0ex}}\Rightarrow \pm 90\xb0=2\alpha \left(\because anglebetweentheaxesis\pm 90\xb0\right)\phantom{\rule{0ex}{0ex}}\Rightarrow \pm 45\xb0=\alpha $

Now,

Slope = $\mathrm{tan}\alpha =\mathrm{tan}\left(\pm 45\xb0\right)=\pm 1$

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